[LeetCode February Challange] Day 1 - Number of 1 Bits
Write a function that takes an unsigned integer and returns the number of ‘1’ bits it has (also known as the Hamming weight).
Note:
- Note that in some languages such as Java, there is no unsigned integer type. In this case, the input will be given as a signed integer type. It should not affect your implementation, as the integer’s internal binary representation is the same, whether it is signed or unsigned.
- In Java, the compiler represents the signed integers using 2’s complement notation. Therefore, in Example 3 above, the input represents the signed integer. -3.
Follow up: If this function is called many times, how would you optimize it?
Example 1:
Input: n = 00000000000000000000000000001011
Output: 3
Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.
Example 2:
Input: n = 00000000000000000000000010000000
Output: 1
Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.
Example 3:
Input: n = 11111111111111111111111111111101
Output: 31
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.
Constraints:
- The input must be a binary string of length 32
Solution
Bit operation
Time complexity : O(log n)
Space complexity : O(1)
class Solution {
public:
int hammingWeight(uint32_t n) {
int ans = 0;
while (0 < n) {
ans += n & 1;
n >>= 1;
}
return ans;
}
};
Built-in function
Time complexity : O(log n)
Space complexity : O(1)
class Solution {
public:
int hammingWeight(uint32_t n) {
return __builtin_popcount(n);
}
};